Answer on Question #79914 - Math – Linear Algebra
Question
Check whether the following system of equations has a solution.
4 x + 2 y + 8 z + 6 w = 3 4x + 2y + 8z + 6w = 3 4 x + 2 y + 8 z + 6 w = 3 2 x + 2 y + 2 z + 2 w = 1 2x + 2y + 2z + 2w = 1 2 x + 2 y + 2 z + 2 w = 1 x + 3 z + 2 w = 3 x + 3z + 2w = 3 x + 3 z + 2 w = 3
Solution
Find a rank of the coefficient matrix A:
A = ( 4 2 8 6 2 2 2 2 1 0 3 2 ) ∼ ( 1 0.5 2 1.5 2 2 2 2 1 0 3 2 ) ∼ ( 1 0.5 2 1.5 0 1 − 2 − 1 0 − 0.5 1 0.5 ) ∼ ( 1 0.5 2 1.5 0 1 − 2 − 1 0 0 0 0 ) . A = \begin{pmatrix}
4 & 2 & 8 & 6 \\
2 & 2 & 2 & 2 \\
1 & 0 & 3 & 2
\end{pmatrix}
\sim
\begin{pmatrix}
1 & 0.5 & 2 & 1.5 \\
2 & 2 & 2 & 2 \\
1 & 0 & 3 & 2
\end{pmatrix}
\sim
\begin{pmatrix}
1 & 0.5 & 2 & 1.5 \\
0 & 1 & -2 & -1 \\
0 & -0.5 & 1 & 0.5
\end{pmatrix}
\sim
\begin{pmatrix}
1 & 0.5 & 2 & 1.5 \\
0 & 1 & -2 & -1 \\
0 & 0 & 0 & 0
\end{pmatrix}. A = ⎝ ⎛ 4 2 1 2 2 0 8 2 3 6 2 2 ⎠ ⎞ ∼ ⎝ ⎛ 1 2 1 0.5 2 0 2 2 3 1.5 2 2 ⎠ ⎞ ∼ ⎝ ⎛ 1 0 0 0.5 1 − 0.5 2 − 2 1 1.5 − 1 0.5 ⎠ ⎞ ∼ ⎝ ⎛ 1 0 0 0.5 1 0 2 − 2 0 1.5 − 1 0 ⎠ ⎞ . Rank ( A ) = 2. \operatorname{Rank}(A) = 2. Rank ( A ) = 2.
Write an augmented matrix of the system of the equations and find her rank:
B = ( 4 2 8 6 3 2 2 2 2 1 1 0 3 2 3 ) ∼ ( 1 0.5 2 1.5 0.75 2 2 2 2 1 1 0 3 2 3 ) ∼ ( 1 0.5 2 1.5 0.75 0 1 − 2 − 1 − 0.5 0 − 0.5 1 0.5 2.25 ) ∼ B = \begin{pmatrix}
4 & 2 & 8 & 6 & 3 \\
2 & 2 & 2 & 2 & 1 \\
1 & 0 & 3 & 2 & 3
\end{pmatrix}
\sim
\begin{pmatrix}
1 & 0.5 & 2 & 1.5 & 0.75 \\
2 & 2 & 2 & 2 & 1 \\
1 & 0 & 3 & 2 & 3
\end{pmatrix}
\sim
\begin{pmatrix}
1 & 0.5 & 2 & 1.5 & 0.75 \\
0 & 1 & -2 & -1 & -0.5 \\
0 & -0.5 & 1 & 0.5 & 2.25
\end{pmatrix}
\sim B = ⎝ ⎛ 4 2 1 2 2 0 8 2 3 6 2 2 3 1 3 ⎠ ⎞ ∼ ⎝ ⎛ 1 2 1 0.5 2 0 2 2 3 1.5 2 2 0.75 1 3 ⎠ ⎞ ∼ ⎝ ⎛ 1 0 0 0.5 1 − 0.5 2 − 2 1 1.5 − 1 0.5 0.75 − 0.5 2.25 ⎠ ⎞ ∼ ∼ ( 1 0.5 2 1.5 0.75 0 1 − 2 − 1 − 0.5 0 0 0 0 2 ) ∼ ( 1 0.5 2 1.5 0.75 0 1 − 2 − 1 − 0.5 0 0 0 0 1 ) . \sim
\begin{pmatrix}
1 & 0.5 & 2 & 1.5 & 0.75 \\
0 & 1 & -2 & -1 & -0.5 \\
0 & 0 & 0 & 0 & 2
\end{pmatrix}
\sim
\begin{pmatrix}
1 & 0.5 & 2 & 1.5 & 0.75 \\
0 & 1 & -2 & -1 & -0.5 \\
0 & 0 & 0 & 0 & 1
\end{pmatrix}. ∼ ⎝ ⎛ 1 0 0 0.5 1 0 2 − 2 0 1.5 − 1 0 0.75 − 0.5 2 ⎠ ⎞ ∼ ⎝ ⎛ 1 0 0 0.5 1 0 2 − 2 0 1.5 − 1 0 0.75 − 0.5 1 ⎠ ⎞ . Rank ( B ) = 3. \operatorname{Rank}(B) = 3. Rank ( B ) = 3. Rank ( A ) ≠ Rank ( B ) \operatorname{Rank}(A) \neq \operatorname{Rank}(B) Rank ( A ) = Rank ( B ) . By Kronecker-Capelli theorem, the given system of linear equations is incompatible, the system has no solution.
Answer: the system has no solution.
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