Question #79907

Find the orthogonal canonical reduction of the quadratic form
x2+y2+z2
1

Expert's answer

2018-08-22T10:23:08-0400

Answer on Question #79907 – Math – Linear Algebra

Question

Find the orthogonal canonical reduction of the quadratic form x2+y2+z2x^{2} + y^{2} + z^{2}.

Solution

A quadratic form in 3 variables Q(x,y,z)Q(x,y,z) is a function of the form Q(x,y,z)=qxxx2+2qxyxy+2qxzxz+qyyy2+2qyzxy+qzzz2Q(x,y,z) = q_{xx}x^{2} + 2\cdot q_{xy}xy + 2\cdot q_{xz}xz + q_{yy}y^{2} + 2\cdot q_{yz}xy + q_{zz}z^{2}. It is known that by changing the system of coordinates (x,y,z)(x,y,z)(x,y,z)\rightarrow (x^{\prime},y^{\prime},z^{\prime}) in some way, any quadratic form can be transformed to a canonical form Q(x,y,z)=D(x,y,z)=dxxx2+dzzy2+dzzz2Q(x,y,z) = D(x^{\prime},y^{\prime},z^{\prime}) = d_{x^{\prime}x^{\prime}}x^{\prime 2} + d_{z^{\prime}z^{\prime}}y^{\prime 2} + d_{z^{\prime}z^{\prime}}z^{\prime 2}. The reduction is called orthogonal if the transformation is defined by an orthogonal matrix.

In the case of this problem, the quadratic form is already a linear combination of the squares of the variables. And the trivial transformation is defined by an orthogonal matrix, i.e. the identity matrix.

Answer:

The quadratic form x2+y2+z2x^{2} + y^{2} + z^{2} is a orthogonal canonical form.

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