Question #70107

The admission fee at an amusement park is $ 1.50 for children and $ 4.00 for adults. On a certain day, 299 people entered the park, and the admission fees collected totaled $936 . How many children and how many adults were admitted?

Expert's answer

Answer on Question #70107 – Math – Algebra

Question

1. The admission fee at an amusement park is $1.50 for children and $4.00 for adults. On a certain day, 299 people entered the park, and the admission fees collected totaled $936. How many children and how many adults were admitted?

Solution

x = number of children, then (299 - x) = number of adults.

Then


1.5x+4(299x)=9362.5x=93611962.5x=260x=104299x=299104=195\begin{array}{l} 1.5 \cdot x + 4 \cdot (299 - x) = 936 \\ -2.5 \cdot x = 936 - 1196 \\ -2.5 \cdot x = -260 \\ x = 104 \\ 299 - x = 299 - 104 = 195 \\ \end{array}


Answer: 104 children, 195 adults.

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