Question #54663

LetVbethesetofallfunctionsthataretwicedifferentiableinRand S={cosx,sinx,xcosx,xsinx}. a)CheckthatSisalinearlyindependentsetoverR.(Hint:Considertheequation a0cosx+a1sinx+a2xcosx+a3xsinx. Putx=0,π,π 2 ,π 4 ,etc.andsolveforai.)
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Expert's answer

2015-09-17T08:10:56-0400

Answer on Question#54663, Math / Linear Algebra

For set of functions sinx,cosx,xcosx,xsinx\text{sinx}, \text{cosx}, \text{xcosx}, \text{xsinx} to be linearly independent, a0cosx+a1sinx+a2cosx+a3sinx=0a_0 \cos x + a_1 \sin x + a_2 \cos x + a_3 \sin x = 0 only when a0=0,a1=0,a2=0,a3=0a_0 = 0, a_1 = 0, a_2 = 0, a_3 = 0 .

Let us evaluate a0cosx+a1sinx+a2cosx+a3sinx=0a_0 \cos x + a_1 \sin x + a_2 \cos x + a_3 \sin x = 0 for x=0,x=π,x=π2,x=π4x = 0, x = \pi, x = \frac{\pi}{2}, x = \frac{\pi}{4} . Obtain:


x=0:a0=0x = 0: a _ {0} = 0x=π:πa2=0x = \pi : - \pi a _ {2} = 0x=π2:a1+π2a3=0x = \frac {\pi}{2}: a _ {1} + \frac {\pi}{2} a _ {3} = 0x=π4:a12+π42a3=0x = \frac {\pi}{4}: \frac {a _ {1}}{\sqrt {2}} + \frac {\pi}{4 \sqrt {2}} a _ {3} = 0


From first two equations, a0=0,a2=0a_0 = 0, a_2 = 0 , and substituting third equation into fourth, obtain a1=0a_1 = 0 and a3=0a_3 = 0 .

Therefore, the set of functions sinx,cosx,xcosx,xsinx\text{sinx}, \text{cosx}, \text{xcosx}, \text{xsinx} are linearly independent.

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