Answer on Question#54663, Math / Linear Algebra
For set of functions sinx , cosx , xcosx , xsinx \text{sinx}, \text{cosx}, \text{xcosx}, \text{xsinx} sinx , cosx , xcosx , xsinx to be linearly independent, a 0 cos x + a 1 sin x + a 2 cos x + a 3 sin x = 0 a_0 \cos x + a_1 \sin x + a_2 \cos x + a_3 \sin x = 0 a 0 cos x + a 1 sin x + a 2 cos x + a 3 sin x = 0 only when a 0 = 0 , a 1 = 0 , a 2 = 0 , a 3 = 0 a_0 = 0, a_1 = 0, a_2 = 0, a_3 = 0 a 0 = 0 , a 1 = 0 , a 2 = 0 , a 3 = 0 .
Let us evaluate a 0 cos x + a 1 sin x + a 2 cos x + a 3 sin x = 0 a_0 \cos x + a_1 \sin x + a_2 \cos x + a_3 \sin x = 0 a 0 cos x + a 1 sin x + a 2 cos x + a 3 sin x = 0 for x = 0 , x = π , x = π 2 , x = π 4 x = 0, x = \pi, x = \frac{\pi}{2}, x = \frac{\pi}{4} x = 0 , x = π , x = 2 π , x = 4 π . Obtain:
x = 0 : a 0 = 0 x = 0: a _ {0} = 0 x = 0 : a 0 = 0 x = π : − π a 2 = 0 x = \pi : - \pi a _ {2} = 0 x = π : − π a 2 = 0 x = π 2 : a 1 + π 2 a 3 = 0 x = \frac {\pi}{2}: a _ {1} + \frac {\pi}{2} a _ {3} = 0 x = 2 π : a 1 + 2 π a 3 = 0 x = π 4 : a 1 2 + π 4 2 a 3 = 0 x = \frac {\pi}{4}: \frac {a _ {1}}{\sqrt {2}} + \frac {\pi}{4 \sqrt {2}} a _ {3} = 0 x = 4 π : 2 a 1 + 4 2 π a 3 = 0
From first two equations, a 0 = 0 , a 2 = 0 a_0 = 0, a_2 = 0 a 0 = 0 , a 2 = 0 , and substituting third equation into fourth, obtain a 1 = 0 a_1 = 0 a 1 = 0 and a 3 = 0 a_3 = 0 a 3 = 0 .
Therefore, the set of functions sinx , cosx , xcosx , xsinx \text{sinx}, \text{cosx}, \text{xcosx}, \text{xsinx} sinx , cosx , xcosx , xsinx are linearly independent.
www.AssignmentExpert.com
Comments