Question #50918

Integrate with respect to x :
∫10xdx

a 4

b 1

c 2

d 1/2

Expert's answer

Answer to question # 50918

Integrate with respect to xx :


01xdx\int_{0}^{1} x \, dx


Solution


01xdx=[x22]01=122022=12\int_{0}^{1} x \, dx = \left[ \frac{x^2}{2} \right]_{0}^{1} = \frac{1^2}{2} - \frac{0^2}{2} = \frac{1}{2}


Answer: 12\frac{1}{2}

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