Question #43815

Let A be an n×n matrix. Then Show that the set, U={uϵRn : Au = - 3un} is a Subspace ofRn

Expert's answer

Answer on Question #43815 – Math – Linear Algebra

Let AA be an n×nn \times n matrix. Then Show that the set, U={uRn:Au=3un}U = \{u \in \mathbb{R}^n : Au = -3un\} is a Subspace of Rn\mathbb{R}^n.

Solution.

Let VV be a vector space over field KK. Suppose that WW is a subset of VV. If WW is a vector space itself (which means that it is closed under operations of addition and scalar multiplication), with the same vector space operations as VV has, then WW is a subspace of VV. Then WW is a subspace of VV if and only if WW satisfies the following condition:

If xWx \in W and yWy \in W then ax+byWax + by \in W for all a,bKa, b \in K.

In our case V=RnV = R^n, W=UW = U and K=RK = R. Let's verify the previous condition

Let xUx \in U and yUy \in U then Ax=3nxAx = -3nx and Ay=3nyAy = -3ny.

Let's consider the combination u=ax+byu = ax + by

Au=A(ax+by)=aAx+bAy=a(3nx)+b(3ny)=3(ax+by)n=3un, so we getAu = A(ax + by) = aAx + bAy = a(-3nx) + b(-3ny) = -3(ax + by)n = -3un, \text{ so we get}

Au=3unAu = -3un, hence UU is a subspace of RnR^n.

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