Question #41200

Let A=
∣2 0∣
∣0 3∣
and B=
∣7 0∣
∣0 11∣
. Find AB

Expert's answer

Answer on Question #41200 – Math – Linear Algebra:

Let A=(2003)A = \begin{pmatrix} 2 & 0 \\ 0 & 3 \end{pmatrix}, B=(70011)B = \begin{pmatrix} 7 & 0 \\ 0 & 11 \end{pmatrix}. Find ABAB.

Solution.


AB=(2003)(70011)=(27+0020+01107+3000+311)=(140033).AB = \begin{pmatrix} 2 & 0 \\ 0 & 3 \end{pmatrix} \begin{pmatrix} 7 & 0 \\ 0 & 11 \end{pmatrix} = \begin{pmatrix} 2 \cdot 7 + 0 \cdot 0 & 2 \cdot 0 + 0 \cdot 11 \\ 0 \cdot 7 + 3 \cdot 0 & 0 \cdot 0 + 3 \cdot 11 \end{pmatrix} = \begin{pmatrix} 14 & 0 \\ 0 & 33 \end{pmatrix}.


Answer.


(140033).\begin{pmatrix} 14 & 0 \\ 0 & 33 \end{pmatrix}.


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