Answer on Question #40993 – Math – Linear Algebra
Question:
Solve the linear equation: 2x+3y=3, x−2y=5 and 3x+2y=7
Solution:
Solve the system:
⎩⎨⎧2x+3y=31x−2y=53x+2y=7
Divide the 1-th equation by 2 and express x by other variables
⎩⎨⎧x=−1.5y+1.51x−2y=53x+2y=7
In 2, 3 equation we substitute x
⎩⎨⎧x=−1.5y+1.51(−1.5y+1.5)−2y=53(−1.5y+1.5)+2y=7
after simplification we get:
⎩⎨⎧x=−1.5y+1.5−3.5y=3.5−2.5y=2.5
Divide the 2-th equation by -3.5 and express y by other variables
⎩⎨⎧x=−1.5y+1.5y=−1−2.5y=2.5
In 3 equation we substitute y
⎩⎨⎧x=−1.5y+1.5y=−1−2.5(−1)=2.5
after simplification we get:
⎩⎨⎧x=−1.5y+1.5y=−10=0
Answer:
{x=3y=−1