Answer on Question #40993 – Math – Linear Algebra
Question:
Solve the linear equation: 2 x + 3 y = 3 2x + 3y = 3 2 x + 3 y = 3 , x − 2 y = 5 x - 2y = 5 x − 2 y = 5 and 3 x + 2 y = 7 3x + 2y = 7 3 x + 2 y = 7
Solution:
Solve the system:
{ 2 x + 3 y = 3 1 x − 2 y = 5 3 x + 2 y = 7 \left\{ \begin{array}{l} 2x + 3y = 3 \\ 1x - 2y = 5 \\ 3x + 2y = 7 \end{array} \right. ⎩ ⎨ ⎧ 2 x + 3 y = 3 1 x − 2 y = 5 3 x + 2 y = 7
Divide the 1-th equation by 2 and express x x x by other variables
{ x = − 1.5 y + 1.5 1 x − 2 y = 5 3 x + 2 y = 7 \left\{ \begin{array}{l} x = -1.5y + 1.5 \\ 1x - 2y = 5 \\ 3x + 2y = 7 \end{array} \right. ⎩ ⎨ ⎧ x = − 1.5 y + 1.5 1 x − 2 y = 5 3 x + 2 y = 7
In 2, 3 equation we substitute x x x
{ x = − 1.5 y + 1.5 1 ( − 1.5 y + 1.5 ) − 2 y = 5 3 ( − 1.5 y + 1.5 ) + 2 y = 7 \left\{ \begin{array}{l} x = -1.5y + 1.5 \\ 1(-1.5y + 1.5) - 2y = 5 \\ 3(-1.5y + 1.5) + 2y = 7 \end{array} \right. ⎩ ⎨ ⎧ x = − 1.5 y + 1.5 1 ( − 1.5 y + 1.5 ) − 2 y = 5 3 ( − 1.5 y + 1.5 ) + 2 y = 7
after simplification we get:
{ x = − 1.5 y + 1.5 − 3.5 y = 3.5 − 2.5 y = 2.5 \left\{ \begin{array}{l} x = -1.5y + 1.5 \\ -3.5y = 3.5 \\ -2.5y = 2.5 \end{array} \right. ⎩ ⎨ ⎧ x = − 1.5 y + 1.5 − 3.5 y = 3.5 − 2.5 y = 2.5
Divide the 2-th equation by -3.5 and express y y y by other variables
{ x = − 1.5 y + 1.5 y = − 1 − 2.5 y = 2.5 \left\{ \begin{array}{l} x = -1.5y + 1.5 \\ y = -1 \\ -2.5y = 2.5 \end{array} \right. ⎩ ⎨ ⎧ x = − 1.5 y + 1.5 y = − 1 − 2.5 y = 2.5
In 3 equation we substitute y y y
{ x = − 1.5 y + 1.5 y = − 1 − 2.5 ( − 1 ) = 2.5 \left\{ \begin{array}{l} x = -1.5y + 1.5 \\ y = -1 \\ -2.5(-1) = 2.5 \end{array} \right. ⎩ ⎨ ⎧ x = − 1.5 y + 1.5 y = − 1 − 2.5 ( − 1 ) = 2.5
after simplification we get:
{ x = − 1.5 y + 1.5 y = − 1 0 = 0 \left\{ \begin{array}{l} x = -1.5y + 1.5 \\ y = -1 \\ 0 = 0 \end{array} \right. ⎩ ⎨ ⎧ x = − 1.5 y + 1.5 y = − 1 0 = 0
Answer:
{ x = 3 y = − 1 \left\{ \begin{array}{l} x = 3 \\ y = -1 \end{array} \right. { x = 3 y = − 1