Question #40793

Let a quadratic form have the expression x2+y2+2z2+2xy+3xz with respect to the
standard basis B1 = f(1;0;0); (0;1;0); (0;0;1)g. Find its expression with respect to the
basis B2 = f(1;1;1); (0;1;0); (0;1;1)g

Expert's answer

Answer on Question#40793 - Math - Linear Algebra

Task:

Let a quadratic form have the expression x2+y2+2z2+2xy+3xzx2 + y2 + 2z2 + 2xy + 3xz with respect to the standard basis B1=f(1;0;0)B1 = f(1;0;0) ; (0;1;0)(0;1;0) ; (0;0;1)g(0;0;1)g . Find its expression with respect to the basis B2=f(1;1;1)B2 = f(1;1;1) ; (0;1;0)(0;1;0) ; (0;1;1)g(0;1;1)g

Solution:

Denote this quadratic form by Q=x2+y2+2z2+2xy+3xzQ = x^{2} + y^{2} + 2z^{2} + 2xy + 3xz ;

The matrix of this quadratic form with respect to the

standard basis B1={f(1;0;0);(0;1;0);(0;0;1)}\mathsf{B}1 = \{\mathsf{f}(1;0;0);(0;1;0);(0;0;1)\} is A=(113/21103/202)\mathsf{A} = \begin{pmatrix} 1 & 1 & 3/2 \\ 1 & 1 & 0 \\ 3/2 & 0 & 2 \end{pmatrix} ;

This means that AA is a symmetric n×nn \times n matrix such that Q=xTAxQ = x^{T}Ax ;

C=(100111101)\mathbf{C} = \left( \begin{array}{lll}1 & 0 & 0\\ 1 & 1 & 1\\ 1 & 0 & 1 \end{array} \right) - is a transformation matrix from B1 to B2;

A1 = C^T A C - matrix of this quadratic form with respect to the basis B2;

Let find A1; A1 = (111010011)\begin{pmatrix} 1 & 1 & 1 \\ 0 & 1 & 0 \\ 0 & 1 & 1 \end{pmatrix} , (11321103202)\begin{pmatrix} 1 & 1 & \frac{3}{2} \\ 1 & 1 & 0 \\ \frac{3}{2} & 0 & 2 \end{pmatrix} , (100111101)=(722721105211)\begin{pmatrix} 1 & 0 & 0 \\ 1 & 1 & 1 \\ 1 & 0 & 1 \end{pmatrix} = \begin{pmatrix} \frac{7}{2} & 2 & \frac{7}{2} \\ 1 & 1 & 0 \\ \frac{5}{2} & 1 & 1 \end{pmatrix} , (100111101)=\begin{pmatrix} 1 & 0 & 0 \\ 1 & 1 & 1 \\ 1 & 0 & 1 \end{pmatrix} =

(9211/221111/213);\left( \begin{array}{c c c} 9 & 2 & 1 1 / 2 \\ 2 & 1 & 1 \\ 1 1 / 2 & 1 & 3 \end{array} \right);


So the expression of QQ with respect to the

basis B2={(1;1;1);(0;1;0);(0;1;1)}\mathrm{B}2 = \{(1;1;1);(0;1;0);(0;1;1)\} is Q1=xTA1x=(xyz)(9211221111213)(xyz)=\mathrm{Q}1 = x^{T}A1x = (xyz)\left( \begin{array}{ccc}9 & 2 & \frac{11}{2}\\ 2 & 1 & 1\\ \frac{11}{2} & 1 & 3 \end{array} \right)\left( \begin{array}{c}x\\ y\\ z \end{array} \right) =

9x2+y2+3z2+4xy+11xz+2yz;9 x ^ {2} + y ^ {2} + 3 z ^ {2} + 4 x y + 1 1 x z + 2 y z;

Answer:

The expression of QQ with respect to the

basis B2={f(1;1;1);(0;1;0);(0;1;1)}\mathrm{B}2 = \{\mathrm{f}(1;1;1);(0;1;0);(0;1;1)\} is Q1=9x2+y2+3z2+4xy+11xz+2yz\mathrm{Q}1 = 9x^{2} + y^{2} + 3z^{2} + 4xy + 11xz + 2yz

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