Question #40301

Find a basis of the subspace of R3 of the solution of the equation X+Y+Z=0 .

Expert's answer

Answer on Question #40301, Math, Linear Algebra

Find a basis of the subspace of R3 of the solution of the equation X+Y+Z=0X + Y + Z = 0.

**Solution.**

To find basis, we need to convert this equation into a vector equation.

Solve the equation for xx.


x=yz.x = -y - z.


Now let yy and zz be parameters.

Letting y=sy = s and z=tz = t, we find that any vector (x,y,z)(x, y, z) that lies in the plane can be written as vector equation


(x,y,z)=(st,s,t)(x, y, z) = (-s - t, s, t)


for all ss and tt.

Separating the parameters, we find that


(x,y,z)=s(1,1,0)+t(1,0,1)(x, y, z) = s(-1, 1, 0) + t(-1, 0, 1)


for all ss and tt.

Therefore, the set {(1,1,0),(1,0,1)}\{(-1,1,0), (-1,0,1)\} is a basis for the plane X+Y+Z=0X + Y + Z = 0.

Answer: {(1,1,0),(1,0,1)}\{(-1,1,0), (-1,0,1)\}

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