Answer on Question #40118, Math, Linear Algebra
What is the dimension of R n R^n R n over R R R ? Write it in vectors?
Answer
Definition: If a vector space V V V has a basis consisting of n n n vectors, then we say that dimension of V V V is n n n . We also write dim ( V ) = n \dim(V) = n dim ( V ) = n .
dim ( R n ) = n . \dim(\mathbb{R}^n) = n. dim ( R n ) = n .
This is because the standard basis
e 1 ‾ = ( 1 , 0 , 0 , … , 0 ) , e 2 ‾ = ( 0 , 1 , 0 , … , 0 ) , … , e n ‾ = ( 0 , 0 , 0 , … , 1 ) \overline{e_1} = (1, 0, 0, \dots, 0), \overline{e_2} = (0, 1, 0, \dots, 0), \dots, \overline{e_n} = (0, 0, 0, \dots, 1) e 1 = ( 1 , 0 , 0 , … , 0 ) , e 2 = ( 0 , 1 , 0 , … , 0 ) , … , e n = ( 0 , 0 , 0 , … , 1 )
consist of n n n elements.
Also
dim ( R n ) = tr ( i d R n ) = tr ( 1 … 0 ⋮ 1 ⋮ 0 … 1 ) = n . \dim(\mathbb{R}^n) = \operatorname{tr}(id_{\mathbb{R}^n}) = \operatorname{tr} \begin{pmatrix} 1 & \dots & 0 \\ \vdots & 1 & \vdots \\ 0 & \dots & 1 \end{pmatrix} = n. dim ( R n ) = tr ( i d R n ) = tr ⎝ ⎛ 1 ⋮ 0 … 1 … 0 ⋮ 1 ⎠ ⎞ = n .