Question #40013

Find the equation of the plane passing through i-j , i+j and k.

Expert's answer

Answer on Question #40013, Math, Linear Algebra

Find the equation of the plane passing through i-j, i+j and k.

Solution

Let's find the equations of the plane that pass through the points A = (1, -1, 0), B = (1, 1, 0) and C = (0, 0, 1).


AB=(11,1(1),00)=(0,2,0);\overline{AB} = (1 - 1, 1 - (-1), 0 - 0) = (0, 2, 0);AC=(01,0(1),10)=(1,1,1).\overline{AC} = (0 - 1, 0 - (-1), 1 - 0) = (-1, 1, 1).


These points belong to the plane if the system has the solution:


AX=λAB+μAC;{x1=μy(1)=2λ+μz0=μ{x101y+121z01=0x+z1=0.\begin{array}{l} \overline{AX} = \lambda \cdot \overline{AB} + \mu \cdot \overline{AC}; \\ \left\{ \begin{array}{l} x - 1 = -\mu \\ y - (-1) = 2\lambda + \mu \\ z - 0 = \mu \end{array} \right. \\ \left\{ \begin{array}{ccc} x - 1 & 0 & -1 \\ y + 1 & 2 & 1 \\ z & 0 & 1 \end{array} \right. = 0 \rightarrow x + z - 1 = 0. \end{array}


Answer: x+z1=0x + z - 1 = 0.

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