Given that the set S= ((1,0,0,0), (0,0,1.0), (5,1,11,0), (-4,0,-6,1)) is a basis of R*, and T= {(1,0,1,0), (0,2,0,3)} is linearly independent. Extend T to a basis of R.
At first, we compute the determinant: . We receive: . Thus, the set indeed contains the basis (the vectors of are linearly independent and vectors in are always linearly dependent). Another basis, which can be received as an extension of , can be found in different ways. For example, we can use Gram-Schmidt orthogonalization. Another way is to consider the matrix: . As we can see, the block is non-degenerate. It means, that we can easily extend the matrix: . The block is also non-degenerate. . Therefore, the respective vectors of matrix are linearly independent. Thus, they are the basis.
Answer: , , and is the basis. It is received as the extension of .
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