Determine which of the following is the solution set of the linear equations below.
3x − y + z = 2
2x − z = 2
The system has an infinite number of solutions because we have 3 variables and only 2 equations:
{3x−y+z=22x−z=2 ⟹ {5x−y=42x−z=2 ⟹ \begin{cases}3x-y+z=2\\ 2x-z=2 \end{cases} \implies \begin{cases} 5x-y=4\\ 2x-z=2 \end{cases} \implies{3x−y+z=22x−z=2⟹{5x−y=42x−z=2⟹{5x−y=4x=12(2+z) ⟹ {5x−y=4x=1+0.5z ⟹ \begin{cases} 5x-y=4\\ x=\frac12(2+z) \end{cases} \implies\begin{cases} 5x-y=4\\ x=1+0.5z \end{cases}\implies{5x−y=4x=21(2+z)⟹{5x−y=4x=1+0.5z⟹ {5(1+0.5z)−y=4x=1+0.5z ⟹ {5+2.5z−y=4x=1+0.5z\begin{cases} 5(1+0.5z)-y=4\\ x=1+0.5z \end{cases}\implies\begin{cases} 5+2.5z-y=4\\ x=1+0.5z \end{cases}{5(1+0.5z)−y=4x=1+0.5z⟹{5+2.5z−y=4x=1+0.5z ⟹ {y=1+2.5zx=1+0.5z ⟹ \implies\begin{cases} y=1+2.5z\\ x=1+0.5z \end{cases}\implies⟹{y=1+2.5zx=1+0.5z⟹ {x=1+0.5zy=1+2.5zz∈R\begin{cases} x=1+0.5z\\ y=1+2.5z\\ z\in R \end{cases}⎩⎨⎧x=1+0.5zy=1+2.5zz∈R
RRR - set of real numbers.
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