A man rows 12 miles downstream on a river in 2 hrs. He requires another 3 hrs. to row back to his starting position. Find the speed of the current and the rate the man can row in still water.
v−rate of manu−speed of the current{2(v+u)=123(v−u)=12⇒{v+u=6v−u=4⇒{v=5u=1v-rate\,\,of\,\,man\\u-speed\,\,of\,\,the\,\,current\\\left\{ \begin{array}{c} 2\left( v+u \right) =12\\ 3\left( v-u \right) =12\\\end{array} \right. \Rightarrow \left\{ \begin{array}{c} v+u=6\\ v-u=4\\\end{array} \right. \Rightarrow \left\{ \begin{array}{c} v=5\\ u=1\\\end{array} \right.v−rateofmanu−speedofthecurrent{2(v+u)=123(v−u)=12⇒{v+u=6v−u=4⇒{v=5u=1
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