a=(1,−1,5),b=(−3,9,−7),c=(−2,−6,h)λ1a+λ2b+λ3c=0λ1=λ2=λ3=0λ1(1,−1,5)+λ2(−3,9,−7)+λ3(−2,−6,h)==(0,0,0)λ1−3λ2−2λ3=0−λ1+9λ2−6λ3=05λ1−7λ2+hλ3=0Δ=∣∣1−15−39−7−2−6h∣∣=9h+90−14++90−3h−42=6h+124=0h=−6124h=−362
If h=−362,h∈(−∞,−362)∪(−362,∞) the vectors a,b,c are linearly independent.
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