Answer to Question #307573 in Linear Algebra for Wes

Question

1/a+bi =c+di

Answer 1

$\frac{1}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2+b^2}.$

$\frac{a-bi}{a^2+b^2}=c+di.$

$c=\frac{a}{a^2+b^2}.$

$d=-\frac{b}{a^2+b^2}.$