Show that if P and Q are vector Subspaces of a vector space V then P ∩ Q is also a vector subspace of V.
Let x,y∈P∩Qx,y\in P\cap Qx,y∈P∩Q and α∈F\alpha \in \mathbb{F}α∈F. We shall show that P∩Q≠ϕP\cap Q\neq \phiP∩Q=ϕ α(x+y)∈P∩Q\alpha(x+y) \in P\cap Qα(x+y)∈P∩Q
Since P and Q are subspaces of V then, P ≠ϕ and Q≠ϕ ⟹ P∩Q≠ϕ\text{Since P and Q are subspaces of V then, P }≠\phi \text{ and } Q≠\phi\implies P\cap Q\neq \phiSince P and Q are subspaces of V then, P =ϕ and Q=ϕ⟹P∩Q=ϕ
Since P and Q are subspaces of V ⟹ α(x+y)∈P and α(x+y)∈Q\text{Since P and Q are subspaces of V }\implies \alpha(x+y) \in P \text{ and } \alpha(x+y) \in QSince P and Q are subspaces of V ⟹α(x+y)∈P and α(x+y)∈Q
Thus, α(x+y)∈P∩Q\alpha(x+y) \in P\cap Qα(x+y)∈P∩Q
Hence, P∩QP\cap QP∩Q is a subspace of VVV
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