Answer to Question #255590 in Linear Algebra for shyla

Question

During an experiment in the lab, Jack, a biologist has a 40% mixture and a 10%mixture of the nutrient that he got from the pawpaw plant. The lecturer posed the question to Jack. How much of each mixture should Jack mix to obtain 25 cm³ of a 28% mixture? [Verify your answer by MATHEMATICA and attach the printout of the commands and output]

Answer 1

Jack need 15 cm³ of 40% and 10 cm³ of 28% mixture.

Let x and y be amounts of the first and the second mixtures, then the first equation (eq1) states, that total volume is 25 cm³.

There are 0.4 x grams of the nutrient in x cm³ of 40% mixture. Accordingly, there are 0.1 y and 0.28*25 grams of the nutrient in y and 25 cm³. So the second equation is based on that fact. The total solution in Mathematica is shown below: