Question #248815

T :ℝ2 → ℝ2 as, 𝑇 ð‘Ĩ, ð‘Ķ = (1, ð‘Ķ) ;is it a linear transformation?


Expert's answer

Here given

T :ℝ2 → ℝ2 , is defined as

T(x,y)=(1,y)

Now,

for T((1,0)+(0,))=T((1,1))=(1,1)for \space T((1,0)+(0,))=T((1,1))=(1,1)

but T((1,0))+T((0,1))=(1,0)+(1,1)=(2,1)T((1,0))+T((0,1))=(1,0)+(1,1)=(2,1)

Thus for (1,0),(0,1)∈R2,T((1,0)+(0,1)≠T((1,0))+T((0,1))(1,0),(0,1)\in\Reals^2,\\T((1,0)+(0,1)\ne T((1,0))+T((0,1))

and T is not a linear transformation.


By definition, a map, T:V(F)→U(F)islineartransformationifT(Îąu+Îēy)=ÎąT(u)+ÎēT(y)∀α,Îē,∈,F andu,y∈VT:V(F)\to U(F) is linear transformation if T(\alpha u+\beta y)=\alpha T(u)+\beta T(y) \forall\alpha, \beta,\in,F \space and u,y\in V

or

equivalently

T(u+y)=T(u)+T(y)∀u,y∈VT(αu)=αT(u)∀α∈F,u∈VT(u+y)=T(u)+T(y)\forall u,y\in V\\T(\alpha u)=\alpha T(u)\forall \alpha \in F,u\in V


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