Let A be an N by N matrix with rank J<N. Prove then that there are N - J linearly independent solutions of the system Ax = 0, and the null space of A has dimension N - J.
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Expert's answer
2013-02-13T11:21:10-0500
Every solution is the solutionto Bx=0, where B is row echelon form. For B we have n-j last zero rows, and these corresponding x_i 's can be choosen linearly independent, and other will be automatically computed, so there will be n-j lin indep solutions.
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