Question #234681

a. Find the orthogonal and normal canonical forms of 2y^2-2yz+2zx-2xy.

b. The operation,* defined by a*b= sin(ab), is a binary operation on N

True or false with full explanation



1
Expert's answer
2021-09-13T05:41:18-0400

1.f(x;y;z)=2y22yz+2zx2xy=(y22yz+z2)+(y22xy+x2)z2+2xzx2=(yz)2+(yx)2(zx)2.f(x;y;z)=2y^2-2yz+2zx-2xy=(y^2-2yz+z^2)+(y^2-2xy+x^2)-z^2+2xz-x^2=(y-z)^2+ (y-x)^2-(z-x)^2.

Let's make the transformation of variables: yz=a;yx=b;zx=c.y-z=a; y-x=b; z-x=c. We have f(a;b;c)=a2+b2c2.f(a;b;c)=a^2+b^2-c^2. It is the orthogonal and normal canonical form.

2.For all a,bNa,b\in N it is exists the unique value sin(ab)\sin (ab) .The domain of the function y=sin(x)y=\sin(x) is RR , and by the properties of this function y=sin(x)y=\sin(x) it is unambiguous. So """*" is a binary operation.


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