Question #225315
4x^2+3y^2+z^2-8xy-6yz+4zx
1
Expert's answer
2021-09-05T18:38:39-0400

4x2+3y2+z28xy6yz+4zx=x2+y2+z22xy2yz+2zx+3x2+2y26xy4yz=(xy+z)2+2(x2+y22xy)+x22xy4yz=(xy+z)2+2(xy)2+x22xy4yz4x^2+3y^2+z^2-8xy-6yz+4zx\\ =x^2+y^2+z^2-2xy-2yz+2zx+3x^2+2y^2-6xy-4yz\\ =(x-y+z)^2+2(x^2+y^2-2xy)+x^2-2xy-4yz\\ =(x-y+z)^2+2(x-y)^2+x^2-2xy-4yz


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