if w is subspace of a vector space V over field F such that dim v=5 and dim w=2 then dim A(w) =
Since w is a subspace of v, we have that,dim(w)+dim(A(w))=dim(v)dim(w)=5β2=3\text{Since w is a subspace of v, we have that,}\\dim(w)+dim(A(w))=dim(v) \\\text{$dim(w) = 5-2=3$}Since w is a subspace of v, we have that,dim(w)+dim(A(w))=dim(v)dim(w)=5β2=3
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