1) T is an isomorphism.
We need to show that T(β) is a basis for W .
The set T(β)={T(β1),…,T(βn)} consists of n vectors. It suffices to show that T(β1),…,T(βn) are linearly independent.
Let i=1∑naiT(βi)=0 for some ai .
Then i=1∑naiT(βi)=i=1∑nT(aiβi)=T(i=1∑naiβi)=0
Since T is an isomorphism, it follows that Tv=0 only if v=0 .
Therefore, i=1∑naiβi=0 . Since β is a basis for V , all ai=0 .
Hence, T(β) is linearly independent.
2) T(β) is a basis for W .
We need to show that T is an isomorphism.
T is injective if and only if Ker T=0 .
Suppose that v∈Ker T and v=i=1∑naiβi for some ai .
Tv=T(i=1∑naiβi)=i=1∑nT(aiβi)=i=1∑naiT(βi)=0.
Since T(β) is a basis for W , it follows that all ai=0 . Then we have that v=0 and Ker T=0 .
T is surjective if and only if for all w∈W there exists v∈V such that Tv=w .
Let w=i=1∑naiT(βi) for some ai .
Then w=i=1∑naiT(βi)=i=1∑nT(aiβi)=T(i=1∑naiβi) , where i=1∑naiβi∈V.
T is injective and surjective. So, T is an isomorphism.
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