A=∣∣510051005∣∣
you cannot find the column X such that A=cX for c∈ R
since A is 3x3 and cX is 3x1
however, we can find X such that AX=cX for some c∈ A
clearly, 5 is an eign calue & A and the compounding eigen vector is
X=⎣⎡00a⎦⎤
foe any a∈ R
we can check that AX=5X
AX=⎣⎡510051005⎦⎤ ⎣⎡00a⎦⎤ =X=⎣⎡005a⎦⎤ =5⎣⎡00a⎦⎤ =5X
as,A=(−10−2+102+100)
AT=[−102+10−2+100]
ATconjugate=(AT)∗=[102−10−2+100] = =[−10−2−102+100]
∴ conjugate transpose of A is -A
Therefpre A is skew-hermitian
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