Question #211572

Group or not group? The set of Mnxn (R) of all nxn matrices under multiplication.


1
Expert's answer
2021-07-19T16:20:19-0400

Question. Group or not group? The set of Mnxn (R) of all nxn matrices under multiplication.


Answer. This set is not a group under multiplication.


Proof. Let AMn×n(R)A\in M_{n\times n}(R), A=(000000000)A=\begin{pmatrix} 0 & 0 & \dots & 0 \\ 0 & 0 & \dots & 0 \\ \dots & \dots & \dots & \dots \\ 0 & 0 & \dots & 0 \end{pmatrix}.

Suppose that matrix AA is invertible (there exists an BMn×n(R)B\in M_{n\times n}(R), such that AB=BA=InA\cdot B=B\cdot A=I_n).

On the another hand, for every matrix CMn×n(R)C\in M_{n\times n}(R) we have AC=CA=0A\cdot C=C\cdot A=0.

Therefore, in the set of all matrices n×nn\times n there exists a non-invertible matrix, so Mn×n(R)M_{n\times n}(R) isn't a group.


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