In January 2025
Answer to Question #208637 in Linear Algebra for Temidayo
Solve the simultaneous equation +=5 and +=1
"\\displaystyle\na_1x + b_1y = 5\\\\\na_2x + b_2y = 1\\\\\n\na_1a_2x + b_1a_2y = 5a_2\\\\\na_1a_2x + a_1b_2y = a_1\\\\\n\n(b_1a_2 - a_1b_2)y = 5a_2 - a_1\\\\\n\ny = \\frac{5a_2 - a_1}{b_1a_2 - a_1b_2}\\\\\n\na_1b_2x + b_1b_2y = 5b_2\\\\\nb_1a_2x + b_1b_2y = b_1\\\\\n\n(a_1b_2 - b_1a_2)x = 5b_2 - b_1\\\\\n\nx = \\frac{5b_2 - b_1}{a_1b_2 - b_1a_2}\\\\"
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