Question #173508

9(b) Consider the system of equations (5)

11 2x1 + x2 + 4x3 =

3x1 + x2 + 5x3 =14

A feasible solution is x1 = ,2 x2 = ,3 x3 = .1 Reduce this feasible solution to a basic

feasible solution.


1
Expert's answer
2021-05-10T13:40:41-0400

2x1+x2=114x32x_1+x_2=11-4x_3

3x1+x2=145x33x_1+x_2=14-5x_3

Δ=2131=1\Delta=\begin{vmatrix} 2 & 1 \\ 3 & 1 \end{vmatrix}=-1

Δ1=114x31145x31=x33\Delta_1=\begin{vmatrix} 11-4x_3 & 1 \\ 14-5x_3 & 1 \end{vmatrix}=x_3-3

Δ2=2114x33145x3=2x35\Delta_2=\begin{vmatrix} 2 & 11-4x_3 \\ 3 & 14-5x_3 \end{vmatrix}=2x_3-5

x1=Δ1/Δ=3x3x_1=\Delta_1/\Delta=3-x_3

x2=Δ2/Δ=52x3x_2=\Delta_2/\Delta=5-2x_3



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