"\\theta=\\cos^{-1}\\bigg(\\frac{\\vec{a}\\cdot \\vec{c}}{ac}\\bigg)" Thus, "\\vec a\\cdot \\vec c=-10+2+8=0\\implies \\theta=\\cos^{-1}(0)=90^\\circ"
"\\vec a +\\vec c=(\\hat i-\\hat j+2\\hat k)+(-10\\hat i-2\\hat j+4\\hat k)=-9\\hat i-3\\hat j+6\\hat k\\\\\n\\implies |\\vec a +\\vec c|=\\sqrt{(-9)^2+(-3)^2+6^2}=\\sqrt{126}"
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