Student has five subjects and 40 hrs available.
So,x1+x2+x3+x4+x5=40
0≤x1≤40,0≤x2≤40,0≤x3≤40,0≤x4≤40,0≤x5≤40,
where x1,x2,x3,x4,x5 are real numbers.
This is the equation whose solution set specifies all possible allocation of time among the five courses which will exhaust the 40 hours.
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