Question #106348
Let λ ∈ R be an eigenvalue of an orthogonal matrix A. Show that λ = ±1.
(Hint: consider the norm of Av, where v is an eigenvector of A associated with the
eigenvalue λ.)

Also, find diagonal orthogonal matrices B, C such that 1 is an eigenvalue of B
and −1 is an eigenvalue of C.
1
Expert's answer
2020-03-24T10:41:54-0400

A square matrix AA is said to be orthogonal if AA=IAA'=I =AA=A'A

where A=A'= Transpose of AA and I=I= Identity matrix.

Suppose λR\lambda \in R be a eigenvalue of AA .

Then there exists a non zero eigenvector XX such that

AX=λXAX=\lambda X ......(1)......(1)

Taking transpose of both sides of the above equality, we get

(AX)=(λX)(AX)'=(\lambda X)'

    \implies XA=XλX'A'=X' \lambda

    \implies XA=λXX'A'=\lambda X'

Multiplying both sides by AXAX we get,

XAAX=λXAXX'A'AX=\lambda X'AX

    \impliesXX=λXλXX'X=\lambda X' \lambda X [from equation (1)]

    XX=λ2XX\implies X'X={ \lambda }^2 X'X

    (1λ2)XX=0\implies (1- { \lambda}^2)X'X=0

Since ,X0    XX0.X \neq0 \implies X'X\neq0.

Therefore,(1λ2)=0(1-\lambda^2)=0

    λ2=1\implies \lambda^2=1

Hence λ=1,1\lambda =1,-1 .

(Proved)(Proved) .

Let B=B= (1001)\begin{pmatrix} 1&0\\ 0&1 \end{pmatrix} which is a diagonal matrix and BB=BB=IBB'=B'B=I

Hence ,BB is an othogonal matrix ,whose eigen values are +1,+1.+1, +1.

Let C=(1001)C=\begin{pmatrix} -1 & 0 \\ 0 & -1 \end{pmatrix} which is a diagonal matrix and CC=CC=ICC'=C'C=I

Hence ,CC is an orthogonal matrix, whose eigen values are 1,1.-1,-1. .




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