A square matrix A is said to be orthogonal if AA′=I =A′A
where A′= Transpose of A and I= Identity matrix.
Suppose λ∈R be a eigenvalue of A .
Then there exists a non zero eigenvector X such that
AX=λX ......(1)
Taking transpose of both sides of the above equality, we get
(AX)′=(λX)′
⟹ X′A′=X′λ
⟹ X′A′=λX′
Multiplying both sides by AX we get,
X′A′AX=λX′AX
⟹X′X=λX′λX [from equation (1)]
⟹X′X=λ2X′X
⟹(1−λ2)X′X=0
Since ,X=0⟹X′X=0.
Therefore,(1−λ2)=0
⟹λ2=1
Hence λ=1,−1 .
(Proved) .
Let B= (1001) which is a diagonal matrix and BB′=B′B=I
Hence ,B is an othogonal matrix ,whose eigen values are +1,+1.
Let C=(−100−1) which is a diagonal matrix and CC′=C′C=I
Hence ,C is an orthogonal matrix, whose eigen values are −1,−1. .
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