Question #105233
Let U, V be subspaces of R^n. Prove that U + V = {u + v : u ∈ U and v ∈ V} is also a subspace of R^n.
1
Expert's answer
2020-03-11T14:08:49-0400

Clearly ,U+V is non empty and zero vector is belongs to this set because 0 belongs to U and V as they are Subspace. Now let

u1,u2Uand v1,v2V.Then u1+v1,u2+v2U+V.Now u1+v1+u2+v2=(u1+u2)+(v1+v2)U+V.u_1 ,u_2 \in U \, and \space v_1 ,v_2 \in V .\,\\ Then \space u_1+v_1 ,u_2+v_2 \in U+V.\,\\ Now \space u_1+v_1+u_2+v_2=(u_1+u_2)+(v_1+v_2)\in U+V.Since Uand VaresubspacesSince \space U \, and \space V \, are \, subspaces .

Let kKk \in K ,where K is the given field.

Therefore,k(u1+u2)=ku1+ku2U+V.k(u_1+u_2)=ku_1+ku_2 \in U+V.

Since U and V are subspace.

Hence U+V is a subspace of RnR^n .




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