Answer to Question #103820 in Linear Algebra for tyler

Question

Graph this equation by plotting three points: y = 3x - 2.


What are your points?

Where does your line cross the x-axis(write as an ordered pair, or if it is not a "nice" point, provide the two numbers it lies between)?

Where does your line cross the y-axis(write as an ordered pair)?

Is the origin on the right or left side of the line?

Answer 1

Solution:

y = 3x - 2 --------- (1)

(1)

Put x= 0 we get y = $-$ 2 , so the first point is (0,$-$ 2).

Put y= 0 we get x= $\frac{2}{3}$ , so the second point is ( $\frac{2}{3}$ , 0).

Put x=1 we get y = 1 , so the third point is (1, 1).

Graph is as follows:

(2)

Points are (0,-2) , ($\frac{2}{3}$ ,0) ,(1,1)

(3)

Line crosses the x-axis at the point ($\frac{2}{3}$ , 0) // the y-coordinate (ordinate) of the x-axis is always zero.

(4)

Line crosses the y-axis at the point (0,-2) // the x-coordinate (abscissa) of the y-axis is always zero.

(5)

Origin(0,0) lies on the left hand side of the line.