Question #52848

Integrate the following expressions.
(integral) (2x^3-3x^2+5x-2)dx
(integral) (5sin2+2cos4)dx
1

Expert's answer

2015-05-29T09:20:21-0400

Answer on Question #52848 – Math – Integral Calculus

Integrate the following expressions:

a) (2x33x2+5x2)dx\int (2x^3 - 3x^2 + 5x - 2)dx;

b) (5sin2+2cos4)dx\int (5\sin 2 + 2\cos 4)dx.

Solution

a) (2x33x2+5x2)dx=12x4x3+52x22x+C\int (2x^3 - 3x^2 + 5x - 2)dx = \frac{1}{2} x^4 - x^3 + \frac{5}{2} x^2 - 2x + C, where CC is an arbitrary real constant.

Here the following formulas were used:

(kf(x))dx=kf(x)dx,k\int (kf(x))dx = k\int f(x)dx, k is a fixed real constant;


(f(x)+g(x))dx=f(x)dx+g(x)dx,\int (f(x) + g(x))dx = \int f(x)dx + \int g(x)dx,(f(x)g(x))dx=f(x)dxg(x)dx,\int (f(x) - g(x))dx = \int f(x)dx - \int g(x)dx,

xndx=xn+1n+1+C\int x^n dx = \frac{x^{n+1}}{n+1} + C, where CC is an arbitrary real constant, nn is integer, n1n \neq -1.

b) (5sin2+2cos4)dx=(5sin2+2cos4)x+C\int (5\sin 2 + 2\cos 4)dx = (5\sin 2 + 2\cos 4)x + C, where CC is an arbitrary real constant.

Here the following formula was used: kdx=kx+C\int kdx = kx + C, where CC is an arbitrary real constant, kk is a fixed real constant.


(5sin2x+2cos4x)dx=(52cos2x+24sin4x)+C=52cos2x+12sin4x+C,\int (5\sin 2x + 2\cos 4x)dx = \left(-\frac{5}{2}\cos 2x + \frac{2}{4}\sin 4x\right) + C = -\frac{5}{2}\cos 2x + \frac{1}{2}\sin 4x + C,


where CC is an arbitrary real constant.

Here the following formulas were used:

(kf(x))dx=kf(x)dx,k\int (kf(x))dx = k\int f(x)dx, k is a fixed real constant;


(f(x)+g(x))dx=f(x)dx+g(x)dx,\int (f(x) + g(x))dx = \int f(x)dx + \int g(x)dx,sin(ax)dx=cos(ax)a+C,\int \sin(ax)dx = -\frac{\cos(ax)}{a} + C,

cos(bx)dx=sin(bx)b+C\int \cos(bx)dx = \frac{\sin(bx)}{b} + C, where CC is an arbitrary real constant, a,ba, b are fixed real constants.

Answer:

a) (2x33x2+5x2)dx=12x4x3+52x22x+C\int (2x^3 - 3x^2 + 5x - 2)dx = \frac{1}{2} x^4 - x^3 + \frac{5}{2} x^2 - 2x + C;

b) (5sin2+2cos4)dx=(5sin2+2cos4)x+C\int (5\sin 2 + 2\cos 4)dx = (5\sin 2 + 2\cos 4)x + C.

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