Answer on Question #52848 – Math – Integral Calculus
Integrate the following expressions:
a) ∫(2x3−3x2+5x−2)dx;
b) ∫(5sin2+2cos4)dx.
Solution
a) ∫(2x3−3x2+5x−2)dx=21x4−x3+25x2−2x+C, where C is an arbitrary real constant.
Here the following formulas were used:
∫(kf(x))dx=k∫f(x)dx,k is a fixed real constant;
∫(f(x)+g(x))dx=∫f(x)dx+∫g(x)dx,∫(f(x)−g(x))dx=∫f(x)dx−∫g(x)dx,∫xndx=n+1xn+1+C, where C is an arbitrary real constant, n is integer, n=−1.
b) ∫(5sin2+2cos4)dx=(5sin2+2cos4)x+C, where C is an arbitrary real constant.
Here the following formula was used: ∫kdx=kx+C, where C is an arbitrary real constant, k is a fixed real constant.
∫(5sin2x+2cos4x)dx=(−25cos2x+42sin4x)+C=−25cos2x+21sin4x+C,
where C is an arbitrary real constant.
Here the following formulas were used:
∫(kf(x))dx=k∫f(x)dx,k is a fixed real constant;
∫(f(x)+g(x))dx=∫f(x)dx+∫g(x)dx,∫sin(ax)dx=−acos(ax)+C,∫cos(bx)dx=bsin(bx)+C, where C is an arbitrary real constant, a,b are fixed real constants.
Answer:
a) ∫(2x3−3x2+5x−2)dx=21x4−x3+25x2−2x+C;
b) ∫(5sin2+2cos4)dx=(5sin2+2cos4)x+C.
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