Answer on Question #52458 – Math – Integral Calculus
∫(x+x1)2dx
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Solution
∫(x+x1)2dx=∫(x2+2x∗x1+x21)dx=∫x2dx+2∫dx+∫x2dx=3x3+2x−x1+C,
where C is an arbitrary real constant.
We used the following formulas:
∫(f(x)+g(x))dx=∫f(x)dx+∫g(x)dx,∫Af(x)dx=A∫f(x)dx,∫xndx=n+1xn+1+C, where C is an arbitrary real constant, n=−1.(a+b)2=a2+2ab+b2.
Answer: 3x3+2x+x1+C.
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