Question #52458

∫ (x+1/x)^2 dx. show step by step solution
1

Expert's answer

2015-05-08T10:09:14-0400

Answer on Question #52458 – Math – Integral Calculus

(x+1x)2dx\int \left(x + \frac {1}{x}\right) ^ {2} d x


Show step by step solution.

Solution

(x+1x)2dx=(x2+2x1x+1x2)dx=x2dx+2dx+dxx2=x33+2x1x+C,\int \left(x + \frac {1}{x}\right) ^ {2} d x = \int \left(x ^ {2} + 2 x * \frac {1}{x} + \frac {1}{x ^ {2}}\right) d x = \int x ^ {2} d x + 2 \int d x + \int \frac {d x}{x ^ {2}} = \frac {x ^ {3}}{3} + 2 x - \frac {1}{x} + C,


where CC is an arbitrary real constant.

We used the following formulas:


(f(x)+g(x))dx=f(x)dx+g(x)dx,\int (f (x) + g (x)) d x = \int f (x) d x + \int g (x) d x,Af(x)dx=Af(x)dx,\int A f (x) d x = A \int f (x) d x,xndx=xn+1n+1+C, where C is an arbitrary real constant, n1.\int x ^ {n} d x = \frac {x ^ {n + 1}}{n + 1} + C, \text{ where } C \text{ is an arbitrary real constant, } n \neq - 1.(a+b)2=a2+2ab+b2.(a + b) ^ {2} = a ^ {2} + 2 a b + b ^ {2}.


Answer: x33+2x+1x+C\frac{x^3}{3} + 2x + \frac{1}{x} + C.

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