Answer on Question #51629 – Math – Integral Calculus
What is the integration of (x−1)(x−2)(x−3)1
Solution
Let
I(x)=∫(x−1)(x−2)(x−3)1dx.
This integral cannot be expressed in elementary functions.
We use Wolfram Mathematica online integrator and find
I(x)=(x−1)(x−2)(x−3)(2i(x−31+1)(x−32+1)(x−3)23⋅F(isinh−1(x−31)∣2)),
where i is imaginary unit, sinh−1(x) is inverse hyperbolic sine, F(x∣m) is elliptic integral of the first kind.
We can simplify it to
I(x)=(x−1)(x−2)(x−3)(2i(x−3x−2)(x−3x−1)(x−3)23⋅F(isinh−1(x−31)∣2))=2i⋅F(isinh−1(x−31)∣2).
Answer: 2i⋅F(isinh−1(x−31)∣2).
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