Question #50940

Integrate with respect to x :
∫1−36x2−5x+2dx

Expert's answer

Answer to question # 50940

Integrate with respect to xx :


(136x25x+2)dx\int (1 - 36x^2 - 5x + 2)dx


Solution


(136x25x+2)dx=(336x25x)dx=3dx36x2dx5xdx=3x36x335x22+C=3x12x352x2+C\begin{aligned} \int (1 - 36x^2 - 5x + 2)dx &= \int (3 - 36x^2 - 5x)dx = \int 3dx - 36\int x^2dx - 5\int xdx \\ &= 3x - 36\frac{x^3}{3} - 5\frac{x^2}{2} + C = 3x - 12x^3 - \frac{5}{2}x^2 + C \end{aligned}


Answer: 3x12x352x2+C3x - 12x^3 - \frac{5}{2}x^2 + C

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