Question #50937

Integrate with respect to v :
∫104v−632v2dv

Expert's answer

Answer on Question #50937 – Math – Integral Calculus

Question. Find indefinite integral:


(104v632v2)dv\int (104v - 632v^2) dv


Solution.


(104v632v2)dv=104v22632v33+C=52v2632v33+C.\int (104v - 632v^2) dv = 104 \cdot \frac{v^2}{2} - 632 \cdot \frac{v^3}{3} + C = 52v^2 - \frac{632v^3}{3} + C.


Answer. (104v632v2)dv=52v2632v33+C.\int (104v - 632v^2) dv = 52v^2 - \frac{632v^3}{3} + C.

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