Question

Integrate with respect to Q:
∫π302sinQ−5cosQdQ

Answer 1

Answer on Question#50936 – Math – Integral Calculus

Question. Integrate with respect to $Q$: $\int_0^\pi (2\sin Q - 5\cos Q)dQ$.

Solution. $\int_0^\pi (2\sin Q - 5\cos Q)dQ = (-2\cos Q - 5\sin Q)\big|_Q^{\frac{\pi}{3}} = -2\cdot \frac{1}{2} -5\cdot \frac{\sqrt{3}}{2} +2 - 0 =$

$$= 1 - \frac {5 \sqrt {3}}{2} = \frac {2 - 5 \sqrt {3}}{2}.$$

Answer. $\frac{2 - 5\sqrt{3}}{2}$

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