Question #50935

Integrate with respect to x :
∫sinxdx

Expert's answer

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Answer on Question #50935 – Math – Integral Calculus

Integrate with respect to x:sinxdxx: \int \sin x \, dx

Solution.


sinxdx=cosx+C,CR.\int \sin x \, dx = -\cos x + C, \quad C \in \mathbb{R}.


Check: ddx(cosx+C)=(sinx)+0=sinx\frac{d}{dx}(-\cos x + C) = -(-\sin x) + 0 = \sin x.

Answer: cosx+C,CR-\cos x + C, \quad C \in \mathbb{R}.


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