www.AssignmentExpert.com
Answer on Question #50935 – Math – Integral Calculus
Integrate with respect to x:∫sinx dxx: \int \sin x \, dxx:∫sinxdx
Solution.
Check: ddx(−cosx+C)=−(−sinx)+0=sinx\frac{d}{dx}(-\cos x + C) = -(-\sin x) + 0 = \sin xdxd(−cosx+C)=−(−sinx)+0=sinx.
Answer: −cosx+C,C∈R-\cos x + C, \quad C \in \mathbb{R}−cosx+C,C∈R.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!