Question

Find the integral with respect to x: ∫cosxsinxdx

Answer 1

Answer to question # 50929

Integrate with respect to $x$ :

$$\int \cos x \sin x \, dx$$

Solution

Let $\cos x = u$, then $du = -\sin x \, dx$. So, we can rewrite integral

$$-\int u \, du = -\frac{u^2}{2} + C$$

According substitution we have

$$-\frac{(\cos x)^2}{2} + C$$

Answer: $-\frac{(\cos x)^2}{2} + C$

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