Question #50926

\int xcos ax2dx with respect to x

A cos3x+c

B sin2x+c

C sec2x+1

D 12asinax2+c

Expert's answer

Question #50926– Math – Integral Calculus


xcosax2dx\int x \cos a x ^ {2} d x


**Solution:**

Let x2=tx^{2} = t, then 2xdx=dt2xdx = dt

Hence:


xcosax2dx=12cosax22xdx=12cosatdt==12asinat+C=12asinax2+C\begin{array}{l} \int x \cos a x ^ {2} d x = \frac {1}{2} \int \cos a x ^ {2} \cdot 2 x d x = \frac {1}{2} \int \cos a t d t = \\ = \frac {1}{2 a} \sin a t + C = \frac {1}{2 a} \sin a x ^ {2} + C \end{array}


**Answer:**


D:12asinax2+CD: \frac {1}{2 a} \sin a x ^ {2} + C


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