Question #50925

Find
∫e^2xdx

Expert's answer

Answer on Question#50925 - <math> - <integral calculus="">

Find e2xdx\int e^{2x}dx

Solution. e2xdx=12e2xd(2x)=(t=2x)=12etdt=12(et+c)=12(e2x+c)\int e^{2x}dx = \frac{1}{2}\int e^{2x}d(2x) = (t = 2x) = \frac{1}{2}\int e^{t}dt = \frac{1}{2}(e^{t} + c) = \frac{1}{2}(e^{2x} + c)

Answer. e2xdx=12(e2x+c)\int e^{2x}dx = \frac{1}{2}(e^{2x} + c), where cRc \in \mathbb{R}

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