Question #50923

Integrate completely with respect to x :
∫21(4x+6)dx

a 12
b 6
c 8
d 16

Expert's answer

Answer on Question #50923 – Math – Integral Calculus

Integrate completely with respect to xx: 21(4x+6)dx\int 21(4x + 6)dx

a 12

b 6

c 8

d 16

Solution

To solve this problem, apply the Newton-Leibniz formula and integral rules for power functions and addition:


12(4x+6)dx=(2x2+6x)12=(222+62)(212+61)=208=12\int_{1}^{2}(4x + 6)dx = (2x^2 + 6x)\big|_{1}^{2} = (2\cdot2^2 + 6\cdot2) - (2\cdot1^2 + 6\cdot1) = 20 - 8 = 12


Answer: a. 12.

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