Answer on Question #50922 – Math – Integral Calculus
Integrate with respect to x x x :
∫ − 2 2 ( x 3 − 3 x 2 + 2 x − 5 ) d x \int_{-2}^{2} (x^3 - 3x^2 + 2x - 5) \, dx ∫ − 2 2 ( x 3 − 3 x 2 + 2 x − 5 ) d x
a. -36
b. 35
c. 40
d. 41
Solution
Apply Newton-Leibniz formula and table integral for the power function:
∫ − 2 2 ( x 3 − 3 x 2 + 2 x − 5 ) d x = ( x 4 4 − x 3 + x 2 − 5 x ) ∣ − 2 2 = = ( 16 4 − 8 + 4 − 10 ) − ( 16 4 + 8 + 4 + 10 ) = − 36 \begin{aligned}
\int_{-2}^{2} (x^3 - 3x^2 + 2x - 5) \, dx &= \left(\frac{x^4}{4} - x^3 + x^2 - 5x\right) \Big|_{-2}^{2} = \\
&= \left(\frac{16}{4} - 8 + 4 - 10\right) - \left(\frac{16}{4} + 8 + 4 + 10\right) = -36
\end{aligned} ∫ − 2 2 ( x 3 − 3 x 2 + 2 x − 5 ) d x = ( 4 x 4 − x 3 + x 2 − 5 x ) ∣ ∣ − 2 2 = = ( 4 16 − 8 + 4 − 10 ) − ( 4 16 + 8 + 4 + 10 ) = − 36
Thus, the answer is a, that is, -36.
**Answer**: -36.
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