Question #50922

Integrate with respect to x :
∫2−2(x3−3x2+2x−5)dx

a -36
b 35
c 40
d 41

Expert's answer

Answer on Question #50922 – Math – Integral Calculus

Integrate with respect to xx :


22(x33x2+2x5)dx\int_{-2}^{2} (x^3 - 3x^2 + 2x - 5) \, dx


a. -36

b. 35

c. 40

d. 41

Solution

Apply Newton-Leibniz formula and table integral for the power function:


22(x33x2+2x5)dx=(x44x3+x25x)22==(1648+410)(164+8+4+10)=36\begin{aligned} \int_{-2}^{2} (x^3 - 3x^2 + 2x - 5) \, dx &= \left(\frac{x^4}{4} - x^3 + x^2 - 5x\right) \Big|_{-2}^{2} = \\ &= \left(\frac{16}{4} - 8 + 4 - 10\right) - \left(\frac{16}{4} + 8 + 4 + 10\right) = -36 \end{aligned}


Thus, the answer is a, that is, -36.

**Answer**: -36.

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