Answer on Question #50468 – Math – Integral Calculus
∫(1+4x)dx÷(1+x) . please solve this problem
Solution
Evaluate
∫(1+4x)dx=∣additive property∣=∫dx+∫4xdx=∣∣formula∫xαdx=α+1xα+1+C∣∣==x+4+11x4+11+C=x+5/4x5/4+C=x+54x⋅4x+C,
where C is an arbitrary real constant.
Finally get
1+x∫(1+4x)dx=1+xx+54x⋅4x+C,
where C is an arbitrary real constant.
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