Answer on Question #46134– Math – Integral Calculus
Question:
Integrate the following expression with respect to x x x :
∫ x ⋅ cos a x 2 ⋅ d x \int x \cdot \cos a x ^ {2} \cdot d x ∫ x ⋅ cos a x 2 ⋅ d x
cos^3x+c
sin2x+c
sec^2x+1
1/2asinax^2+c
Solution:
Let us change the variable of integration
t = a x 2 . t = a x ^ {2}. t = a x 2 .
Then the differential d x dx d x takes the form
d x = d t a = d t 2 t a . d x = d \sqrt {\frac {t}{a}} = \frac {d t}{2 \sqrt {t a}}. d x = d a t = 2 t a d t .
Therefore
∫ x ⋅ cos a x 2 ⋅ d x = ∫ t a ⋅ cos t ⋅ d t 2 t a = 1 2 a ∫ cos t ⋅ d t . \int x \cdot \cos a x ^ {2} \cdot d x = \int \sqrt {\frac {t}{a}} \cdot \cos t \cdot \frac {d t}{2 \sqrt {t a}} = \frac {1}{2 a} \int \cos t \cdot d t. ∫ x ⋅ cos a x 2 ⋅ d x = ∫ a t ⋅ cos t ⋅ 2 t a d t = 2 a 1 ∫ cos t ⋅ d t .
Consequently
1 2 a ∫ cos t ⋅ d t = sin t 2 a + const = sin a x 2 2 a + const . \frac {1}{2 a} \int \cos t \cdot d t = \frac {\sin t}{2 a} + \text{const} = \frac {\sin a x ^ {2}}{2 a} + \text{const}. 2 a 1 ∫ cos t ⋅ d t = 2 a sin t + const = 2 a sin a x 2 + const .
Thus the final answer is
∫ x ⋅ cos a x 2 ⋅ d x = sin a x 2 2 a + const . \int x \cdot \cos a x ^ {2} \cdot d x = \frac {\sin a x ^ {2}}{2 a} + \text{const}. ∫ x ⋅ cos a x 2 ⋅ d x = 2 a sin a x 2 + const .
Answer: the last answer is correct
∫ x ⋅ cos a x 2 ⋅ d x = sin a x 2 2 a + const . \int x \cdot \cos a x ^ {2} \cdot d x = \frac {\sin a x ^ {2}}{2 a} + \text{const}. ∫ x ⋅ cos a x 2 ⋅ d x = 2 a sin a x 2 + const .
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