Question

Integrate completely with respect to x :
∫10(7−4x)^2dx

79/3
14/15
81/70
16/3

Answer 1

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Answer on Question # 46056 – Math – Integral Calculus

Task:

Integrate completely with respect to $x$ :

$$\int 10(7-4x)^\wedge 2\,dx$$

79/3

14/15

81/70

16/3

Solution:

$$\int_{0}^{1} (7-4x)^2 dx = \int_{0}^{1} (49-56x + 16x^2) dx = (49x - 28x^2 + \frac{16x^3}{3}) \Big|_{0}^{1} = \frac{79}{3}$$

Answer: 79/3.