Question

Integrate with respect to x :
∫2−2(x^3−3x^2+2x−5)dx
2-2 is written 2 supper, -2 sub

-36
35
40
41

Answer 1

Answer on Question #46055 – Math - Integral Calculus

Integrate with respect to $x$ :

$$\int_{-2}^{2} (x^3 - 3x^2 + 2x - 5) \, dx$$

Solution.

$$\int_{-2}^{2} (x^3 - 3x^2 + 2x - 5) \, dx = \left\{ \frac{x^4}{4} - \frac{3x^3}{3} + \frac{2x^2}{2} - 5x \right\} \Big|_{-2}^{2} = \{0 - 16 + 0 - 20\} = -36.$$

We used Newton – Leibnitz formula.

Answer: -36

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